Question

The energy of activation for the reaction 2 HI → H2 + I2 is 180. kJ·mol−1...

The energy of activation for the reaction 2 HI → H2 + I2 is 180. kJ·mol−1 at 556 K. Calculate the rate constant using the equation k = Ae^(−Ea/RT). The collision diameter for HI is

3.5 ✕ 10−8 cm. Assume that the pressure is 1.00 atm.

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