Question

The activation energy for the reaction H2(g) + I2(g) --> 2HI(g) is changed from 184 kJ/mol...

The activation energy for the reaction H2(g) + I2(g) --> 2HI(g) is changed from 184 kJ/mol to 59.0 kJ/mol at 600 K by the introduction of a Pt catalyst. Calculate the value of the ratio rate(catalyzed)/rate(uncatalyzed).

A) 1.00

B) 7.62 x 10^10

C) 1.38

D) 0.321

E) none of these

I know the answer is B, But I want a detail solution.

Homework Answers

Answer #2

answered by: anonymous
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