2) Consider the reaction: I2 (s) + H2 (g) → 2 HI (g)
a) Calculate the value of the equilibrium constant Kp.
b) Calculate ΔGrxn at PHI = 2.55 atm, PH2 = 0.221 atm. Consider excess I2(s)
I2 (s) + H2 (g) → 2 HI (g)
ΔGo rxn = ΔGof products - ΔGoreactants
= 2 x 1.7 - 0
= 3.4 kJ/mol
ΔGo = - R T ln Kp
3.4 = - 8.314 x 10^-3 x 298 x ln Kp
Kp = 0.254
Q = P2HI / PH2 = (2.55)^2 / 0.221
= 29.42
ΔGrxn = ΔGo rxn + R T ln Q
= 3.4 + 8.314 x 10^-3 x 298 x ln 29.42
ΔGrxn = 11.8 kJ/mol
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