Question

"The ease of intramolecular formation of a particular ring size generally follows the order 5 >...

"The ease of intramolecular formation of a particular ring size generally follows the order 5 > 6 > 3 > 7 > 4 > 8." Can someone offer a clear explanation for this please? Thank you in advanced! I know it has something to do with entropy and ring strain but i'm not 100% sure

Homework Answers

Answer #1

The intramolecular formation of a particular ring size generally follows the order 5 > 6 > 3 > 7 > 4 > 8 because the Intramolecular formations are more fast as compared to the intermolecular reactions. Thus reacting species are relatively close to each other. Also there are no geometrical limitations which can resist the intramolecular reaction.

We know that the reactivity depends on the chemical reactions but along with the type of chemical reaction reactivity also depends on the ring size. 5 and 6 membered rings are formed so rapidly.

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