moles of CH4 = mass / molar mass
= 4.00 / 16
= 0.25
moles of He = 2/ 4 = 0.5
total moles = 0.25 + 0.5 = 0.74
T = 273 K
P = 1 atm
P V = n R T
1 x V = 0.75 x 0.0821 x 273
V = 16.8 L
volume of the samole = 16.8 L
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