A sample of gas contains 0.1400 mol of CH4(g) and 0.2800 mol of O2(g) and occupies a volume of 14.9 L. The following reaction takes place: CH4(g) + 2O2(g)CO2(g) + 2H2O(g) Calculate the volume of the sample after the reaction takes place, assuming that the temperature and the pressure remain constant.
According to reaction 1 mole CH4 react with 2 mole O2 give 1 mole of CO2 and 2 mole of H2O therefore
in the reactant 0.1400 mole CH4 react with 0.2800 mole O2 give 0.14 mole of CO2 and 0.2800 mole of H2O
total mole of reactant = 0.1400 + 0.2800 = 0.4200 mole
total mole of product = 0.1400 + 0.2800 = 0.4200 mole
no. of mole of reactant gas = no. of mole of product gas therefore at same tempreture and pressure product gas occupy volume = reactant gas = 14.9 L
volume of the sample after the reaction takes place = 14.9 L
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