Question

A gas mixture contains 13.60g of N2, 2.00g of H2, and 30.00g of CH4. What is the mole fraction of H2 in the mixture?

Answer 1

Solution :-

To calculate the mole fraction of the H2we need to calculate the moles of the each gas

Moles = mass / molar mass

Moles of N2 = 13.60 g / 28.014 g per mol = 0.48547 mol

Moles of H2 = 2.00 g / 2.0158 g per mol =0.99216 mol

Moles of CH4 = 30.00 g / 16.04 g per mol =1.8703 mol

Now lets calculate the mole fraction of the H2

Mole fractionH2 = moles of H2 / total moles

                       = 0.99216 /(0.48547+0.99216+1.8703)

                       =0.296

Therefore mole fraction of the H2 = 0.296