Question

Calculate the volume of CO2 that reacts with 1.00 gram of LiOH according to the equation given below. Assume the reaction goes to completion at a pressure of 1.00 atm and temperature of 298K. MW Li = 6.94 g/mol; MW O = 16.0 g/mol; MW H = 1.01 g/mol; MW C = 12.01 g/mol; R = 0.08206 (L*atm)/(mol*K). 2LiOH(s) + CO2(g) → Li2CO3(s) + H2O(g)

Answer 1

2 LiOH (s) + CO2 (g) Li2CO3(s) + H2O(g)

Moles of LiOH = Amount taken / Molar mass = 1 / 23.95 = 0.04175

According to the balanced equation,

2 moles of LiOH react with 1 mole of CO2

0.04175 moles of LiOH will react with 0.02088 moles of CO2

Volume of CO2 will be calculated using ideal gas equation,

PV = nRT

1 V = 0.02088 0.08206 298

V = 0.5106 L

Volume of CO2 that reacts with 1.00 gram of LiOH = 0.5106 L.