Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2NaN3(s)⟶2Na(s)+3N2(g) Calculate the value of work, w, for the system if 24.0 g NaN3 reacts completely at 1.00 atm and 22 °C.
W=?J
Molar mass of NaN3 = 1*MM(Na) + 3*MM(N)
= 1*22.99 + 3*14.01
= 65.02 g/mol
mass of NaN3 = 24.0 g
mol of NaN3 = (mass)/(molar mass)
= 24.0/65.02
= 0.3691 mol
From balanced chemical reaction, we see that
when 2 mol of NaN3 reacts, 3 mol of N2 is formed
mol of N2 formed = (3/2)* moles of NaN3
= (3/2)*0.3691
= 0.5537 mol
we have:
P = 1.0 atm
n = 0.5537 mol
T = 22.0 oC
= (22.0+273) K
= 295 K
we have below equation to be used:
P * V = n*R*T
1 atm * V = 0.5537 mol* 0.0821 atm.L/mol.K * 295 K
V = 13.41 L
W = -Pext(Vf-Vi)
P = 1.0atm
Vi = 0.0 L
Vf = 13.41 L
put values in above expression
W = -Pext(Vf-Vi)
W = -1.0atm (13.41L - 0.0L)
W = -13.41 atm.L
W = -13.41 *101.33 J
W = -1359 J
Answer: -1359 J
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