Automotive air bags inflate when a sample of sodium azide, NaN3, is very rapidly decomposed.
2NaN3(s) --> 2Na(s) + 3N2(g)
What mass of sodium azide is required to produce 2.6 ft3 (73.6 L) of nitrogen gas with a density of 1.25 g/L?
Volume of nitrogen gas produced = 73.6 L; the density of nitrogen gas = 1.25 g/L.
Therefore, mass of nitrogen gas produced = (73.6 L)*(1.25 g/1 L) = 92 g
Now write the balanced chemical equation:
2 NaN3 (s) -------> 2 Na (s) + 3 N2 (g)
As per the balanced equation, the molar ratio of nitrogen gas and NaN3 = 3:2.
Molar mass of nitrogen gas = 28.0134 g/mol.
Therefore, moles of N2 produced in the reaction = (92 g)/(28.0134 g/mol) = 3.284 mole.
Now, moles of NaN3 required = (3.284 mole N2)*(2 mole NaN3/3 mole N2) = 2.189 Mole NaN3.
Molar mass of NaN3 = 65.0099 g/mol.
Therefore, mass of NaN3 required = (2.189 mole)*(65.0099 g/1 mole) = 142.3067 g ≈ 142.307 g (ans).
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