Question

sodium azide decomposes to form N2 in automobile collision by the following reaction.
2NaNa3(s)=2Na(s)+3N2(g)
a. how many miles of N2 gas are produced by decomposition 52.0g of NaN3?

b. what volume of N2 in liters would be produced in the above reaction at 27℃ and 1 ATM pressure (R=0.0821 L.atm/K.mol

Answer 1

2NaN₃(s)=2Na(s)+3N2(g)

a)

in given reaction 2 moles of NaN₃ gives 3 moles of N₂

1 mole of NaN₃ gives 3/2 moles of N₂

given 52 g of NaN₃

molar mass of NaN₃ = 65 g/mol

no of moles of NaN₃ intially present = 52 g/ 65 g/mol = 0.8 mol of NaN₃

so 0.8 moles of NaN₃ will give = 0.8 * 3/2 moles of N₂ = 1.2 moles of N₂   Answer a)

b)

considering this as ideal gas

PV = NRT

V = NRT/P = 1.2 * 0.0821 * ( 273+27) / 1 = 29.556 L Answer b)

mol * L.atm/mol.K * K / atm =L