Question

Based on this balanced equation:

2LiOH + H2S  → Li2S  + 2H2O


How many moles of Li2S will be produced from 116.07 g of LiOH and excess H2S?

Answer 1

Molar mass of LiOH = 1*MM(Li) + 1*MM(O) + 1*MM(H)

= 1*6.968 + 1*16.0 + 1*1.008

= 23.976 g/mol

mass of LiOH = 116.07 g

mol of LiOH = (mass)/(molar mass)

= 116.07/23.976

= 4.8411 mol

we have the Balanced chemical equation as:

2LiOH ---> 1Li2S

From balanced chemical reaction, we see that

when 2 mol of LiOH reacts, 1 mol of Li2S is formed

mol of Li2S formed = (1/2)* moles of LiOH

= (1/2)*4.8411

= 2.4205 mol

Answer: 2.4205 mol