Question

For each of the following balanced chemical equations, calculate how many grams of the products listed...

For each of the following balanced chemical equations, calculate how many grams of the products listed would be produced by complete reaction of 0.320 mol of the first reactant.

(a) AgNO3(aq) + LiOH(aq) → AgOH(s) + LiNO3(aq)

AgOH g
LiNO3 g

Homework Answers

Answer #1

(a)

AgNO3(aq) + LiOH(aq) → AgOH(s) + LiNO3(aq)

In this balanced chemical equations

1 mole of AgNO3 reacts with 1 mole of LiOH to produce 1 mole of AgOH and 1 mole of  LiNO3.

1 mole of AgNO3 produces 1 mole of AgOH and 1 mole of  LiNO3.

0.32 mole of AgNO3 produces 0.32 mole of AgOH and 0.32 mole of  LiNO3.

Molar mass of AgOH = 124.88 g/mol

1 mole of AgOH = 124.88 g

0.32 mole of AgOH = (0.32 x 124.88) g = 39.96 g

Molar mass of LiNO3 = 68.95 g/mol

1 mole of  LiNO3 = 68.95 g

0.32 mole of LiNO3 = (0.32 x 68.95) g = 22.06 g

AgOH​ = 39.96 g and LiNO3 = 22.06 g

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