Consider the following balanced reaction between hydrogen and nitrogen to form ammonia:
3H2(g) + N2(g)→2NH3(g)
How many moles of NH3 can be produced from 24.0 mol of H2 and excess N2?
Express the number of moles to three significant figures.
3H2(g) + N2(g) → 2NH3(g)
Fom the bance equation, 3 mol H2 = 2 mol NH3
Then, 24.o mol H2 = (24.0 x 2 / 3 ) = 16.0 mol of NH3 will be formed.
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