Question

# Consider the following balanced reaction between hydrogen and nitrogen to form ammonia: 3H2(g) + N2(g)→2NH3(g) How...

Consider the following balanced reaction between hydrogen and nitrogen to form ammonia:

3H2(g) + N2(g)→2NH3(g)

How many moles of NH3 can be produced from 24.0 mol of H2 and excess N2?

Express the number of moles to three significant figures.

3H2(g)        +    N2(g)         →              2NH3(g)

Fom the bance equation, 3 mol H2 = 2 mol NH3

Then, 24.o mol H2 = (24.0 x 2 / 3 ) = 16.0 mol of NH3 will be formed.

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