Question

Given the following equations and Ho values, determine the heat of reaction (kJ) at 298 K...

Given the following equations and Ho values, determine the heat of reaction (kJ) at 298 K for the reaction

2 OF2(g) + 2 S(s) SO2(g) + SF4(g) OF2(g) + H2O(l) O2(g) + 2 HF(g) Ho /kJ = -276.6 SF4(g) + 2 H2O(l) 4 HF(g) + SO2(g) Ho /kJ = -827.5 S(s) + O2(g) SO2(g) Ho /kJ = -296.9

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Answer #1

2 OF2(g) + 2 S(s) —> SO2(g) + SF4(g)

OF2(g) + H2O(l) —>O2(g) + 2 HF(g) Ho /kJ = -276.6

SF4(g) + 2 H2O(l) —>4 HF(g) + SO2(g) Ho /kJ = -827.5

S(s) + O2(g) —> SO2(g) Ho /kJ = -296.9

Lets number the reaction as 0, 1, 2, 3 from top to bottom

required reaction should be written in terms of other reaction

This is Hess Law

required reaction can be written as:

reaction 0 = +2 * (reaction 1) -1 * (reaction 2) +1 * (reaction 3)

So, deltaHo rxn for required reaction will be:

deltaHo rxn = +2 * deltaHo rxn(reaction 1) -1 * deltaHo rxn(reaction 2) +1 * deltaHo rxn(reaction 3)

= +2 * (-276.6) -1 * (-827.5) +1 * (-296.9)

= -22.6 KJ

Answer: -22.6 KJ

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