Question

The standard enthalpy change for this reaction is -731 kJ/mol at 298 K. 2 N2(g) +...

The standard enthalpy change for this reaction is -731 kJ/mol at 298 K. 2 N2(g) + 4 H2(g) + 3 O2(g) = 2 NH4NO3(s) ΔrH° = -731 kJ/mol Calculate the standard enthalpy change for the reaction N2(g) + 2 H2(g) + 3/2 O2(g) = NH4NO3(s) at 298 K.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the enthalpy change (ΔrH) for the reaction below,         N2(g) + 3 F2(g) → 2...
Calculate the enthalpy change (ΔrH) for the reaction below,         N2(g) + 3 F2(g) → 2 NF3(g) given the bond enthalpies of the reactants and products. Bond Bond Enthalpy (kJ/mol×rxn) N–N 163 N=N 418 N≡N 945 F–F 155 N–F 283
Consider the reaction at 298 K: N2 (g) + 2 O2 (g) --> 2 NO2 (g)...
Consider the reaction at 298 K: N2 (g) + 2 O2 (g) --> 2 NO2 (g) The value of ΔHo formation of NO2 (g) is known to be 34.0 kJ/mol, while the value of K is 5.86 x 10-19. Determine the absolute entropy of N2 (g) at 298 K if So O2 = 205 J/K mol and So NO2 = 240 J/K mol. (a) 76.3 J/K (b) 133 J/k (c) 190 J/K (d) 304 J/K (e) 507 J/K
Given the standard reaction enthalpies for the following two reactions: (1) 2Pb(s) + O2(g) = 2PbO(s).........
Given the standard reaction enthalpies for the following two reactions: (1) 2Pb(s) + O2(g) = 2PbO(s)...... ΔrH° = -434.6 kJ/mol (2) 2Zn(s) + O2(g) = 2ZnO(s)........ΔrH° = -696.6 kJ/mol calculate the standard enthalpy change for the reaction: (3) PbO(s) + Zn(s) =Pb(s) + ZnO(s)......ΔrH° = ?
Calculate the standard enthalpy of formation of Ga2H6(g) (in kJ/mol) from the following data: 2 Ga(s)...
Calculate the standard enthalpy of formation of Ga2H6(g) (in kJ/mol) from the following data: 2 Ga(s) + 3/2 O2(g)-->Ga2O3(s).   ΔHo = –1188 kJ/mol Ga2H6(g) + 3 O2(g)-->Ga2O3(s) + 3 H2O(l). ΔHo = –2158 kJ/mol H2(g) + 1/2 O2(g)--> H2O(g) ΔHo = –242 kJ/mol H2O(l)-->H2O(g) ΔHo = +44 kJ/mol 2 Ga(s) + 3 H2(g)-->Ga2H6(g). ΔHo = ? kJ/mol
A scientist measures the standard enthalpy change for the following reaction to be -133.5 kJ :...
A scientist measures the standard enthalpy change for the following reaction to be -133.5 kJ : NH4NO3(aq)N2O(g) + 2 H2O(l) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of NH4NO3(aq) is kJ/mol.
Given the standard reaction enthalpies for these two reactions: (1) 2C(s) + 2H2(g) = C2H4(g)...... ΔrH°...
Given the standard reaction enthalpies for these two reactions: (1) 2C(s) + 2H2(g) = C2H4(g)...... ΔrH° = 52.3 kJ/mol (2) 2C(s) + 3H2(g) = C2H6(g)......ΔrH° = -84.7 kJ/mol calculate the standard reaction enthalpy for the reaction: (3) C2H4(g) + H2(g) = C2H6(g)......ΔrH° = ?
1.) Using enthalpies of formation, calculate the standard change in enthalpy for the thermite reaction. The...
1.) Using enthalpies of formation, calculate the standard change in enthalpy for the thermite reaction. The enthalpy of formation of Fe3O4 is −1117 kJ/mol. 8 Al(s) + 3 Fe3O4(s) → 4 Al2O3(s) + 9 Fe(s) 2. a) Nitroglycerin is a powerful explosive, giving four different gases when detonated. 2 C3H5(NO3)3(l) → 3 N2(g) + 1/2 O2 (g) + 6 CO2(g) + 5 H2O(g) Given that the enthalpy of formation of nitroglycerin, ΔHf°, is −364 kJ/mol, calculate the energy (heat at...
Calculate the standard enthalpy change for the reaction 2 Al(s) + Fe2O3(s)                               
Calculate the standard enthalpy change for the reaction 2 Al(s) + Fe2O3(s)                                           2 Fe(s) + Al2O3(s)   Given that 2 Al(s) +   3/2 O2 (g)                             Al2O3(s)     ΔH rxn = -1669.8 kJ/mol 2 Fe (s)     +    3/2 O2 (g)                              Fe2O3(s)    ΔH rxn = -822.2 kJ/mol
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm...
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction N2(g)+3H2(g)==<>2NH3(g) the standard change in Gibbs free energy is Delta G=-72.6 kJ/mol. What is Delta G for this reaction at 298 K when the partial pressures are P N2 = 0.200 atm, P H2 = 0.150 atm, and P NH3 = 0.900 atm
Consider the following data at 298 K: Compound ∆Hf° (kJ mol−1) H2S (g) -20.5 H2O (g)...
Consider the following data at 298 K: Compound ∆Hf° (kJ mol−1) H2S (g) -20.5 H2O (g) -242 For the reaction   4 Ag(s) + 2 H2S(g) + O2(g) --> 2 Ag2S(s) + 2 H2O(g)    at a temperature of 25 °C, ∆H° = −507 kJ Calculate the ∆Hf° of Ag2S (s) is (in kJ mol−1): -285.5 -32 -64 + 475