The standard enthalpy change for this reaction is -731 kJ/mol at 298 K. 2 N2(g) + 4 H2(g) + 3 O2(g) = 2 NH4NO3(s) ΔrH° = -731 kJ/mol Calculate the standard enthalpy change for the reaction N2(g) + 2 H2(g) + 3/2 O2(g) = NH4NO3(s) at 298 K.
Get Answers For Free
Most questions answered within 1 hours.