How I can calculate the resonance energy from the enthalpy of formation and energy bonds for an aromatic compound.
Determination of resonance energy
Resonance energy is the extra energy released from the molecule for extra stability ( due to resonance )
If a compound exhibits resonance, there is a considerable difference between the enthalpies of formation as calculated from bond energies and those determined experimentally. As an example we may consider the dissociation of benzene.
C6H6 (g) ———> 6C(g) + 6H(g)
Assuming that benzene ring consists of three single and three double bonds (Kekule’s structure) the calculated dissociation energy comes out to be 5384.1 KJ from bond energies data.
ΔHd = 3ΔHC–C + 3ΔHC=C + 6ΔHC–H
The experimental value is known to be 5535.1 KJ/mol. Evidently, the energy required for the dissociation of benzene is 151 KJ more that the calculated value 5384.1 KJ. The difference of 151 KJ gives the resonance energy of benzene.
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