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The standard molar enthalpy of formation, of diborane cannot be determined directly because the compound cannot...

The standard molar enthalpy of formation, of diborane cannot be determined directly because the compound cannot be prepared by reaction of boron and hydrogen. However, the value can be calculated. Calculate the standard enthalpy of formation of gaseous diborane(B2H6) using the following thermochemical information:

i) 4B(s) + 3O2(g) --> WB2O3(S) = -2509.1kJ

ii) 2H2(g) + O2(g) --> 2H2O(l) = - 571.7kJ

iii) B2H6(g) + 3O2(g) --> B2O3(s) + 3H2O(l) = -2147.5 kJ

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