The complete combustion of cyclohexane occurs according to the following equation:
C6H12(g) + 9O2(g) → 6CO2(g) + 6H2O(l)
For this process, ΔcombHo(298 K) = -3952 kJ mol-1. If values of ΔfHo(298 K) for CO2(g) and H2O(l) are -394 and -286 kJ mol-1, respectively, what is the value of ΔfHo(C6H12, g, 298K)?
we have:
deltaHo rxn = -3952.0 KJ/mol
Hof(O2(g)) = 0.0 KJ/mol
Hof(CO2(g)) = -394.0 KJ/mol
Hof(H2O(l)) = -286.0 KJ/mol
we have the Balanced chemical equation as:
C6H12(g) + 9 O2(g) ---> 6 CO2(g) + 6 H2O(l)
deltaHo rxn = 6*Hof(CO2(g)) + 6*Hof(H2O(l)) - 1*Hof( C6H12(g)) - 9*Hof(O2(g))
-3952.0 = 6*(-394.0) + 6*(-286.0) - 1*Hof(C6H12(g)) - 9*(0.0)
Hof(C6H12(g)) = -128 KJ/mol
Answer: -128 KJ/mol
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