Question

A quantity of 5.0g of nitrogen occuppies a glass vessel at 455 mm Hg a temperature...

A quantity of 5.0g of nitrogen occuppies a glass vessel at 455 mm Hg a temperature of 456 Celcius.

1. how many moles of nitrogen (N2) is this equivalent to?

2. What volume of nitrogen is generated?

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Answer #1

Moles of nitrogen= mass of nitrogen/molar mass

molar mass of nitrogen = 28 g/mole,

moles of nitrogen = 5/28= 0.178

Gas law equation can be used to calculate the volume of gas for the given conditions of pressure ( P), temperature (T) and no of moles (n)

If pressure is expressed in atm, temperature in K, R in 0.0821 L.atm/mole.K, Volume of gas can be calculated from

PV= nRT, V= nRT/P

n= 0.178, R=0.0821 L.atm/mole.K, P= 455mm Hg= 455/760 atm =0.598 atm, T= 4560c, since T (K)= T(deg.c)+273= 456+273 K=729K, n= 0.178*0.0821*729/0.598=17.82 L

A quantity of 5.0g of nitrogen occuppies a glass vessel at 455 mm Hg a temperature of 456 Celcius.

1. how many moles of nitrogen (N2) is this equivalent to?

2. What volume of nitrogen is generated?

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