Question

1.A helium-filled weather balloon has a volume of
**811** L at **23** °C and
**750** mm Hg. It is released and rises to an altitude
of **8.69** km, where the pressure is
**281** mm Hg and the temperature is
**-34** °C. The volume of the balloon at this altitude
is ______ L.

2.

A sample of **hydrogen** gas occupies a volume of
**9.89** L at **44** °C and
**0.944** atm.

If it is desired to **decrease** the volume of the gas
sample to **8.88** L, while
**increasing** its pressure to **1.29**
atm, the temperature of the gas sample at the new volume and
pressure must be_______ °C.

3.A sample of **hydrogen** gas collected at a
pressure of **1.11** atm and a temperature of
**16.0**°C is found to occupy a volume of
**29.9** liters. How many moles of
**H _{2}** gas are in the sample?_____ mol

4.A sample of **argon** gas collected at a pressure
of **0.836** atm and a temperature of
**281** K is found to occupy a volume of
**604** milliliters. How many moles of
**Ar** gas are in the sample? _____mol

Answer #1

1) PV= nRT

n of He= (750mmHg/760mmHg x 1atm) x 811L/0.082L.atm/mol.K x 296K = 32.97 mol

the moles of gas at beginning are the same as the moles at the end.

V= 32.97 mol x 0.082L.atm/mol.K x 239 K/(281mmHg/760mmHg x 1atm) = 1747.6 L

2) mol H2= 0.944atm x 9.89L/0.082L.atm/mol.K x 317K= 0.359 mol

Final T:

T= 1.29atm x 8.88L/0.359 mol x 0.082L.atm/mol.K= 389K

3) moles H2= 1.11atm x 29.9L/0.082L.atm/mol.K x 289K= 1.4 mol

4) moles Ar= 0.836atm x 0.604L/0.082L.atm/mol.K x 281K= 0.022 mol

A gas-filled weather balloon has a volume of 60.0 L at ground
level, where the pressure is 763 mmHg and the temperature is 20.9
°C. After being released, the balloon rises to an altitude where
the temperature is –7.29 °C and the pressure is 0.0638 atm. What is
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A helium-filled weather balloon has a volume of 567 L at 20.9°C
and 758 mmHg. It is released and rises to an altitude of 8.24 km,
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