Question

Consider a galvanic cell consisting of: Fe2++2e−Fe2++2e- →→ FeFe -0.44 Al3++3e−Al3++3e- →→ AlAl -1.66 Write the...

Consider a galvanic cell consisting of:

Fe2++2e−Fe2++2e- →→ FeFe -0.44
Al3++3e−Al3++3e- →→ AlAl -1.66

Write the reaction occurring at the anode: Use spaces only before and after a plus sign. For example, the reaction: Fe2++2e−→FeFe2++2e-→Fe would be entered as: Fe^2+ + 2e^- →→ Fe

→→

Write the reaction occurring at the cathode:

→→

Write the reaction for the galvanic cell:

l  lI  l

Calculate the E0cell for the cell.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Constants Fe2+ + 2e− = Fe(s) E º =−0.44 V; O + 4H+ + 4e− 2H2O...
Constants Fe2+ + 2e− = Fe(s) E º =−0.44 V; O + 4H+ + 4e− 2H2O E º =−1.23 V 2)In acid solution, the half cells Fe2+(aq) | Fe(s) and O2(g) | H2O are linked to create a spontaneous, galvanic cell. a) Calculate Eºcell _____________ b) Which reaction occurs at the cathode _______________________________ c) Write the overall reaction for the cell ___________________________________ d) Write the shorthand notation for the anode (anode || cathode).
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2++2e−→FeFe2++2e-→Fe  would be entered as: Fe^2+ + 2e^- →→ Fe Galvanic Cell Consisting of: Cu2++2e− →→ Cu 0.34 Zn2++2e− →→ Zn -0.76 E0cell Measured...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2++2e−→FeFe2++2e-→Fe  would be entered as: Fe^2+ + 2e^- →→ Fe Galvanic Cell Consisting of: Zn2++2e− →→ Zn -0.76 Mg2++2e− →→ Mg -2.37 E0cell Measured...
Consider a galvanic cell based on the following half reactions: E° (V) Al3+ + 3e- →...
Consider a galvanic cell based on the following half reactions: E° (V) Al3+ + 3e- → Al -1.66 Ba2+ + 2e- → Ba -2.90 If this cell is set up at 25°C with [Ba2+] = 2.50 × 10-3M and [Al3+] = 4.00 × 10-2M, the expected cell potential is ____ V
Consider the following half-reactions: Ag+ (aq) + e- --> Ag(s) E cell = 0.80 VV Cu2+(aq)...
Consider the following half-reactions: Ag+ (aq) + e- --> Ag(s) E cell = 0.80 VV Cu2+(aq) + 2e- --> Cu(s) E cell = 0.34 V Pb2+(aq) + 2e- --> Pb(s) E cell = -0.13 V Fe2+(aq) + 2e- --> Fe(s) E cell = -0.44 V Al3+ (aq) + 3e- --> Al(s) E cell = -1.66 V Which of the above metals or metal ions will oxidize Pb(s)? a. Ag+(aq) and Cu2_(aq) b. Ag(s) and Cu(s) c. Fe2+(aq) and Al3+(aq) d....
A standard galvanic cell is constructed in which a Cu2+ | Cu+ half cell acts as...
A standard galvanic cell is constructed in which a Cu2+ | Cu+ half cell acts as the cathode. Which of the following statements are correct? Hint: Refer to a table of standard reduction potentials. (Choose all that apply.) As the cell runs, anions will migrate from the Cu2+|Cu+ compartment to the other compartment. Cu+ is oxidized at the cathode. The anode compartment could be Ag+|Ag. The anode reaction could be Fe -> Fe2+ + 2e-. In the external circuit, electrons...
A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential Cl2(g)+2e−→...
A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential Cl2(g)+2e−→ 2Cl−(aq)   E0red = +1.359V NO−3(aq)+4H+(aq)+3e−→ NO(g)+2H2O(l)   E0red = +0.96V Answer the following questions about this cell. Write a balanced equation for the half-reaction that happens at the cathode.   Write a balanced equation for the half-reaction that happens at the anode.   Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written.   Do you have enough...
Consider a galvanic cell based upon the following half reactions: Fe3+ + 3e- → Fe -0.0036...
Consider a galvanic cell based upon the following half reactions: Fe3+ + 3e- → Fe -0.0036 V Cu2+ + 2e- → Cu 0.34 V How many of the following responses are true? 1. Increasing the mass of the Cu will change the initial potential of the cell 2. Fe is being oxidized during the reaction 3. Increasing the concentration of Cu2+ (assuming no volume change) will decrease the potential of the cell 4. Decreasing the concentration of Fe3+ (assuming no...
Write the cell notation for an electrochemical cell consisting of an anode where Ni(s) is oxidized...
Write the cell notation for an electrochemical cell consisting of an anode where Ni(s) is oxidized to Ni2+(aq) and a cathode where Fe3+(aq) is reduced to Fe2+(aq) at a platinum electrode. Assume all aqueous solutions have a concentration of 1 mol/L and gases have a pressure of 1 bar. Write the cell notation for an electrochemical cell consisting of an anode where Zn (s) is oxidized to Zn2+(aq) and a cathode where Ag+(aq) is reduced to Ag (s) . Assume...
Electrochemical Cell Potentials Table 1: Electrochemical Cell Potentials Cell Measured Total Potential from Multimeter (V)1 Individual...
Electrochemical Cell Potentials Table 1: Electrochemical Cell Potentials Cell Measured Total Potential from Multimeter (V)1 Individual Half-Cell Potentials Cell Reactions5 ΔG (kJ)6 (Cu) Electrode Standard Potential (V)2 Metal Electrode Experimental Potential (V)3 Metal Electrode Theoretical Potential (V)4 Metal Electrode Potential % Error Cu | Sn 0.469 0.34 V 0.34-0.469 =-0.129 Cathode:       Cu2+ + 2e- -> Cu Anode:            Sn ->Sn2++ 2e- Net:          Cu2+ + Sn -> Cu + Sn2+ Cu | Al 0.796 0.34 V 0.34-0.796 =-0.456 Cathode:   Cu2+ +...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT