Question

1. (a) Aluminum is alloyed with 10 atomic percent of the following elements: Li, Si, Cu...

1. (a) Aluminum is alloyed with 10 atomic percent of the following elements: Li, Si, Cu and Au. Determine the weight % for each case.

(b) Repeat problem but for 10 wt.% of each element determine the atomic %.

(c) What is the density of an alloy of Al-13 wt.% Au?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
[1]- An alloy of silicon and iron (Si-Fe) has 0.25 wt% of Si. If the density...
[1]- An alloy of silicon and iron (Si-Fe) has 0.25 wt% of Si. If the density and atomic weight are 2.33 ? ??3 and 28 ? ??? for silicon and 7.87 ? ??3 and 55.85 ? ??? for iron, calculate: a) Atomic percentage of silicon and iron. b) Density of iron in the alloy ( ?? ?3 ). c) Average atomic weight of the alloy ( ? ??? ). d) Number of moles of silicon and iron.
3) Determine the following for a Ti6Al4V femoral head component of a hip implant considering that...
3) Determine the following for a Ti6Al4V femoral head component of a hip implant considering that the mass of the component is 3Ib, and the weight percent composition of the alloy is: 90%Ti, 6%Al, 4%V. Atomic Mass: Ti= 47.9; Al=27; V=50.9. ' a) The mass (in grams) of each element in the implant b) The number of moles of each element in the implant c) The atom percentage composition of the implant
--Given Values-- Atomic Radius (nm) = 0.116 FCC Metal = Gold BCC Metal: = Sodium Temperature...
--Given Values-- Atomic Radius (nm) = 0.116 FCC Metal = Gold BCC Metal: = Sodium Temperature ( C ) = 1017 Metal A = Tin Equilibrium Number of Vacancies (m-3) = 6.02E+23 Temperature for Metal A = 369 Metal B = Gallium 1) If the atomic radius of a metal is the value shown above and it has the face-centered cubic crystal structure, calculate the volume of its unit cell in nm3? Write your answers in Engineering Notation.          ...
1. Aluminum and iron are both important structural metals. Suppose they are processed into the FCC...
1. Aluminum and iron are both important structural metals. Suppose they are processed into the FCC and BCC structures. Of these four possible structures (FCC Al, BCC Al, FCC Fe, BCC Fe), which one has the a) lowest unit cell volume, and b) lowest theoretical density? The radius of Al is 0.1431 nm and the radius of Fe is 0.1241 nm. 2. An unknown metal has a BCC structure, density of 7.25 g/cm3, and atomic weight of 50.99 g/mol. Determine...
For the first eighteen elements, the electrons fill the principal energy levels (electron shells), as predicted...
For the first eighteen elements, the electrons fill the principal energy levels (electron shells), as predicted by simple rules. In other words, electrons occupy the lowest electron shell that is not filled. The formula 2n2 is used to calculate the maximum capacity of each electron shell. (10 pts) Complete the table below by filling in all the missing information. You may use your periodic table. Element Atomic # Electrons present in n = 1 n = 2 n = 3...
Complete the information below using the online periodic tables provided in the procedure. Element   Atomic Number...
Complete the information below using the online periodic tables provided in the procedure. Element   Atomic Number Effective Nuclear Charge 1st Ionization Energies (kJ/mol) Atomic Radius2 (pm) Electro- negativity Values3 Density of solid4 (kg/m3) Number of stable isotopes H 1 N/a 1312 37 2.2 88 He 2 N/a 2372 N/a Li 3 1.69 520 0.98 Be 4 900 B 5 801 82 2460 2 C 6 1087 77 2267 3 N 7 3.83 75 3.04 O 8 4.45 3.44 F 9...
1. The solubility product, Ksp, for aluminum hydroxide, Al(OH)3, is 1.9 ✕ 10−33 at 25°C. What...
1. The solubility product, Ksp, for aluminum hydroxide, Al(OH)3, is 1.9 ✕ 10−33 at 25°C. What is the molar solubility of aluminum hydroxide in a solution containing 0.061 M KOH at 25°C? Answer in molarity.    2. Complete the following table of data for NaCl. (Assume the density of water is 1.00 g/mL.) T (°C) Solubility (g/100. g) Concentration (M) Ksp ΔG (kJ/mol) 13.0 36.8 25.0 37.1 37.0 37.5 49.0 38.1 61.0 38.7 73.0 39.5 85.0 40.4 Use a graph...
1. Briefly explain the difference between self-diffusion and interdiffusion. 2. (a) Compare interstitial and vacancy atomic...
1. Briefly explain the difference between self-diffusion and interdiffusion. 2. (a) Compare interstitial and vacancy atomic mechanisms for diffusion. (b) Cite two reasons why interstitial diffusion is normally more rapid than vacancy diffusion. 3. A sheet of BCC iron 2 mm thick was exposed to a carburizing gas atmosphere on one side and a decarburizing atmosphere on the other side at 675�C. After reaching steady state, the iron was quickly cooled to room temperature. The carbon concentrations at the two...
Section 2: Using the MARS or SPIM simulator develop a program that will implement the following...
Section 2: Using the MARS or SPIM simulator develop a program that will implement the following conditional statement. If ( n is even) { n = n / 2; } else { n = 3 * n + 1; } In this case, n is to be input by the user (assume they input a non-negative value), the conditional is performed, and the resulting n is to be output. Again, use the system calls for input, output, and exiting the...
Problem: Utilize the Tabulation Error Function Value Table from your Examination Booklet. --Given Values-- Concentration of...
Problem: Utilize the Tabulation Error Function Value Table from your Examination Booklet. --Given Values-- Concentration of Nitrogen (wt%): = 0.38 Position in mm = 8.5 Diffusion Coefficient for Nitrogen in Iron at 700℃ = 9.70E-10 Nitrogen in Iron Heat Treatment Time (hours): = 13 Carburizing Time (hrs): = 10 Steel Alloy Case Depth (mm): = 3 Steel Alloy New Case Depth (mm) = 8.8 Activation Energy kJ/mol: = 107 Temperature for Problem 3 (Celsius): = 821 - = Data for...