Question

1. Aluminum and iron are both important structural metals. Suppose they are processed into the FCC and BCC structures. Of these four possible structures (FCC Al, BCC Al, FCC Fe, BCC Fe), which one has the a) lowest unit cell volume, and b) lowest theoretical density? The radius of Al is 0.1431 nm and the radius of Fe is 0.1241 nm.

2. An unknown metal has a BCC structure, density of 7.25 g/cm3, and atomic weight of 50.99 g/mol. Determine the atomic radius of the metal and its likely identify.

3. Niobium has an atomic radius of 0.1430 nm and a density of 8.57 g/cm3. Does it have an FCC or BCC structure

4. Draw the following unit cells and label each atom with its point coordinates:

a) BCC

b) FCC

Answer #1

Niobium (Nb) has an atomic radius of 0.1430 nm and a density of
8.57 g/cm^3. Determine whether it has an FCC or a BCC crystal
structure.

Niobium (Nb) has an atomic radios of 0.1430 nm and a density of
8.57 g/cm^3. Determine whether it has an FCC or a BCC crystal
structure.

Show if lead is an FCC or a BCC crystal structure.
Lead (Pb) has an atomic radius of 0.175 nm and a density
of 11.35 g/cm3 . Use this information to determine whether it has
an FCC or a BCC crystal structure.
Please also provide the correct units.

1) For a metal that has the face-centered cubic (FCC) crystal
structure, calculate the atomic radius if the metal has a density
of (8.000x10^0) g/cm3 and an atomic weight of
(5.80x10^1) g/mol. Express your answer in
nm.
2) Consider a copper-aluminum solid solution containing
(7.82x10^1) at% Al. How many atoms per cubic centimeter
(atoms/cm^3) of copper are there in this solution?
Take the density of copper to be 8.94 g/cm3 and the
density of aluminum to be 2.71 g/cm3.

BCC (body-centered cubic) crystal structure is one of common
crystal structuresfor metals. Please do the following
questions.
(a) Describe what is a BCC structure and draw a BCC unit
cell.
(b) Calculate the radius of a vanadium (V) atom, given that
V has a BCCcrystal structure, a density of 5.96 g/cm3,
and an atomic weight of 50.9 g/mol.

--Given Values--
Atomic Radius (nm) = 0.116
FCC Metal = Gold
BCC Metal: = Sodium
Temperature ( C ) = 1017
Metal A = Tin
Equilibrium Number of Vacancies (m-3) = 6.02E+23
Temperature for Metal A = 369
Metal B = Gallium
1) If the atomic radius of a metal is the value shown above and it
has the face-centered cubic crystal structure, calculate the volume
of its unit cell in nm3? Write your answers in
Engineering Notation.
...

A-What is the trend of atomic size in the periodic table and
why?
B-Determine the bonding type of given atoms (Fe-Fe, Ca-Cl, O-O,
H-H)
C-Calculate the density of Al, given its atomic radius and
crystal structure.
D-Calculate the atomic packing factor for FCC and BCC
structures
E-Compute the elongation due to thermal expansion of given
material.
F-Given the vacancy concentration, calculate
Evf
G-How can edge dislocation move? Draw illustrations.
H-Why are vacancies important to dislocation motions?
I-What is the mechanism...

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