Question

The inversion of sucrose according to the reaction C12H22O11 +H2O --> 2C6H12O6 was observed at 25C...

The inversion of sucrose according to the reaction C12H22O11 +H2O --> 2C6H12O6 was observed at 25C and the experimental times adn concentrations are given below. The initial concentration of sucrose was 1.0023 M

Time (minutes): 0 | 30 | 60 | 90 | 130  

Sucrose inverted (product), M 0 | 0.1001 | 0.1946 | 0.2770 | 0.3726

Show the table and three graphs needed to determine the order of the reaction.

Use the graph to determine the rate constant.

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Homework Answers

Answer #1

The given values are

Time(min) [Sucrose] M ln[Sucrose] 1/[Sucrose]
30 0.1001 -2.301585593 9.99000999
60 0.1946 -1.636809109 5.138746146
90 0.277 -1.283737773 3.610108303
130 0.3726 -0.987249821 2.683843264


=>The plot between [Sucrose] vs time is a straight line then it iszero order.

=> The plot between ln[Sucrose] vs time is a straight line then it is first order.

=>The plot between 1/[Sucrose] vs time is a straight line then it is second order.

From the above graphs the best fit is Zero order fit with R2=0.993.

So the order of the reaction is Zero, the slope of the line is equall to rate constant.

So rate constant k=0.0271 M/min.

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