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how many grams of N2 (28.01 g/mole) can be obtained by reacting 24.5 g of NH3...

how many grams of N2 (28.01 g/mole) can be obtained by reacting 24.5 g of NH3 (17.03 g/mole) with 30.8 g of O2 (MW=32.00 g/mole)?

4 NH3(g) +3 O2(g) -------> 2 N2(g) + 6H2O(l)

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