Question

Complete the following table. [ H3O+ ] [ OH− ] pH pOH Acidic or Basic? a)...

Complete the following table.

[

H3O+

]

[

OH

]

pH pOH Acidic
or Basic?
a)

6.4 × 10−3

× 10(select)−12−16−10−18−14−8

b)

___ × 10(____)

9.3 × 10−3

c)

_____ × 10(__)
× 10(select)−4−10−14−6−8−12 11.68

d)

____ × 10(__)
× 10(select)−3−11−73−5 9.05

e)

____ × 10( __ )

2.3 × 10−8

Homework Answers

Answer #1

the formulas that is use ful is

[H3O+] [OH-] = 1.0 x 10-14

pH = -log[H3O+]

pOH = -log[OH-]

pH + pOH = 14

Part A

[H3O+] = 6.4 × 10−3

[OH-] = 1.0 x 10-14 / 6.4 × 10−3 = 1.56 x 10-12

pH = -log(6.4 × 10−3) = 2.19

pOH = 14-2.19 = 11.8

acidic

Part b

[OH-] = 9.3 × 10−3

[H3O+] = 1.0 x 10-14 / 9.3 × 10−3 = 1.07 x 10-12

pH = -log[1.07 x 10-12] = 11.97

pOH = 14 - 11.97 = 2.03

Basic

Part C

pOH = 11.68

pH = 14-11.68 = 2.32

[H3O+] = 10-pH = 10-2.32 = 4.8 x 10-3

[OH-] = 10-pOH = 10-11.68 = 2.1 x 10-12

acidic

Part D

pH = 9.05

pOH = 14 - 9.05 = 4.95

[H3O+] = 10-pH = 10-9.05 = 8.9 x 10-10

[OH-] = 10-pOH = 10-4.95 = 1.12 x 10-5

basic

Part e

[OH-] = 2.3× 10−8

[H3O+] = 1.0 x 10-14 /2.3 × 10−8 = 4.34 x 10-7

pH = -log[4.34 x 10-7] = 6.36

pOH = 14 - 6.36 = 7.63

slightly acidic (or nuetral)

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