Complete the following table:
[H3O+] |
[OH-] |
pH |
Acidic, Basic, or Neutral? |
10.0 |
Basic |
||
1 x 10-5 M |
|||
1 x 10-2 M |
|||
11.3 |
1st row:
pH = 10
[H3O+] = 10^-pH =10^-10 = 1*10^-10 M
[OH-] = 10^-14 / [H3O+] = 10^-14 / (10^-10) = 1*10^-4 M
since pH is more than 7, it is basic
2nd row:
[OH-] = 1*10^-5 M
[H3O+] = 10^-14 / [OH-] = 10^-14 / (1*10^-5) = 1*10^-9 M
pH = -log [H3O+] = -log (1*10^-9)= 9
since pH is more than 7, it is basic
3rd row:
[H3O+] = 1*10^-2 M
pH = -log [H3O+] = -log (1*10^-2)= 2
[OH-] = 10^-14 / [H3O+] = 10^-14 / (1*10^-2) = 1*10^-10 M
since pH is less than 7, it is acidic
4th row:
pH = 11.3
[H3O+] = 10^-pH =10^-11.3 = 5.01*10^-12 M
[OH-] = 10^-14 / [H3O+] = 10^-14 / (5.01*10^-12) = 2*10^-3 M
since pH is more than 7, it is basic
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