Question

Complete the following table by calculating the missing entries and indicating whether the solution is acidic or basic.

[H+]	[OH−]	pH	pOH	Acidic or basic?
7.7×10−3M
	3.5×10−10M
		8.24
			5.73

Answer 1

H+ = 7.7×10−3M

OH- = (10^-14)/(7.7*10^−3) = 1.29870*10^-12

ph = -log(H) = -log(7.7*10^−3 = 2.11350

pOH = 14-pH = 14-2.11350 = 11.8865

this is acidic sicen pH < 7

OH- = 3.5*10^−10

H+ = (10^-14)/(3.5*10^−10) =0.00002857

ph = -log(H) = -log(0.00002857) = 4.54408

pOH = 14-pH = 14-4.54408 = 9.455

3)

pH = 8.24

H+ = 10^-pH = 10^-8.24 = 5.75439

poh = 14-ph = 14-8.24 = 5.76

[OH-] = 10^-poh = 10^-5.76 = 0.0000017378

this is basic

4)

pOH = 5.73

pH = 14-´poh = 14-5.73 = 8.27

H* = 10^-pH = 10^-5.73 = 0.00000186208

OH- = 10^-poh = 10^-8.27 = 5.37*!0^-9

this is basic