Complete the following table. (All solutions are at 25 ∘C.)
[H3O+] | [OH−] | pH | Acidic or Basic |
3.5×10−3 | _____ | _____ | _____ |
_____ | 3.8×10−7 | _____ | _____ |
1.8×10−9 | _____ | _____ | _____ |
_____ | _____ | 7.15 | _____ |
[H3O+]2, [H3O+]4 = [OH−]1, [OH−]3, [OH−]4 = pH1, pH2, pH3, = Complete the fourth column. Enter your answers separated by commas. |
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basic rules:
Kw = [H+][OH-] = 10^-14
pOH = -log(OH)
pH = -log(H)
14 = pH + pOH
then
a)
H = 3.5*10^-3
pH = -log(H) = -log(3.5*10^-3) = 2.4559
pOH =14-pH = 14-2.4559 = 11.5441
OH = 10^-pOH = 10^-11.5441 = 2.85693*10^-12
b)
[OH-] = 3.8*10^-8
pOH = -log(3.8*10^-8) = 7.420
pH = 14-pOH =14-7.420= 6.58
[H+] = 10^-pH = 10^-6.58 = 2.6302*10^-7
c)
[H+]= 1.8*10^-9
pH = -log(H) = -log(1.8*10^-9) = 8.7447
pOH =14-pH = 14-8.74479 = 5.25521
OH = 10^-pOH = 10^-5.25521=0.00000555635
finally
d)
pH = 7.15
[H+] = 10^-pH = 10^-7.15 = 7.07945*10^-8
pOH= 14-7.15= 6.85
[OH-] = 10^-pOH = 10^-6.85 = 1.4125*10^-7
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