Question

What is the specific rotation of a 15.1:84.9 mixture of cholesterol and its enantiomer?

What is the specific rotation of a 15.1:84.9 mixture of cholesterol and its enantiomer?

Homework Answers

Answer #1

Specific rotation of cholesterol is not given.

From website Specific rotation was taken

Specific Rotation: [α]25 = -34 to -38° (https://www.sigmaaldrich.com/content/dam/sigma-aldrich/docs/Sigma/Product_Information_Sheet/c8667pis.pdf)

I took as  [α]25 = -34°

ee of the  cholesterol = 84.9 - 15.1 = 69.8 %

% ee = observed specific rotation x 100 / specific rotation of pure enantiomer

observed specific rotation = % ee x specific rotation of pure enantiomer /100

observed specific rotation = 69.8 x -34 /100 = -23.73 %

The enantiomer of cholesterol = +23.73%

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