Consider the titration of 20.0 mL of 0.0800 M
H2NNH2 (a weak base; Kb =
1.30e-06) with 0.100 M HNO3. Calculate the pH after the
following volumes of titrant have been added:
(a) 0.0 mL pH = |
(b) 4.0 mL pH = |
(c) 8.0 mL pH = |
(d) 12.0 mL pH = |
(e) 16.0 mL pH = |
(f) 24.0 mL pH = |
Get Answers For Free
Most questions answered within 1 hours.