Calculate the standard entropy, ΔS°rxn, of the following reaction at 25.0 °C using the data in this table. The standard enthalpy of the reaction, ΔH°rxn, is –633.1 kJ·mol–1. 3C2H2(g)==>C6H6(l)
Delta S rxn =
Then calculate the standard gibbs free energy of the reaction Delta G rxn
Delta G rxn=
3C2H2(g)==>C6H6(l)
ΔH°rxn, = ΔH°f products -ΔH°f reactans
= 49.08-3*227.48 = -633.36KJ
ΔS°rxn, = ΔS°f products -ΔS°f reactans
= 173.4 -3*200.9 = -429.4J/Mole-K = -0.4294Kj/mole-K
ΔG0 = ΔH-TΔS
=- 633.1-298*-0.4294 = -505.14KJ
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