Question

Use Hess's Law to calculate the enthalpy of reaction, ΔH rxn, for the reaction in bold...

Use Hess's Law to calculate the enthalpy of reaction, ΔH rxn, for the reaction in bold below given the following chemical steps and their respective enthalpy changes. Show ALL work!

2 C(s) + H2(g) → C2H2(g) ΔH°rxn = ?

1. C2H2(g) + 5/2 O2(g) → 2CO2 (g) + H2O (l) ΔH°rxn = -1299.6 kJ

2. C(s) + O2(g) → CO2 (g) ΔH°rxn = -393.5 kJ

3. H2(g) + ½ O2(g) → H2O (l) ΔH°rxn = -285.8 kJ

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Hess’s Law b) Calculate the ∆H for the reaction: Ti(s) + 2Cl2 (g) → TiCl4 (l)...
Hess’s Law b) Calculate the ∆H for the reaction: Ti(s) + 2Cl2 (g) → TiCl4 (l) Using the following chemical equations and their respective enthalpy changes: Ti(s) + 2Cl2 (g) → TiCl4 (g) ∆H = -763 kJ TiCl4 (l) → TiCl4 (g) ∆H = 41 kJ b) Calculate the ∆H for the reaction: 2CO(g) + O2 (g) → 2CO2 (g) Using the following chemical equations and their respective enthalpy changes: 2C(s) + O2 (g) → 2CO(g) ∆H = -221.0 kJ...
Calculate DH for the reaction 2C(s) + H2(g)                 C2H2(g) given the following chemical equations and their...
Calculate DH for the reaction 2C(s) + H2(g)                 C2H2(g) given the following chemical equations and their respective enthalpy changes: C2H2(g) +    O2(g)                2CO2(g) + H2O DH = -1299.6kJ        C(s) + O2(g)         CO2(g)                         DH = -393.5kJ       H2(g) +    O2(g)              H2O(l)                     DH = -285.8kJ Please help!!! I am completely lost! How do I start, what are the steps?
We can use Hess's law to calculate enthalpy changes that cannot be measured. One such reaction...
We can use Hess's law to calculate enthalpy changes that cannot be measured. One such reaction is the conversion of methane to ethylene: 2CH4(g)⟶C2H4(g)+2H2(g) Calculate the ΔH∘ for this reaction using the following thermochemical data: CH4(g)+2O2(g)⟶CO2(g)+2H2O(l) ΔH∘=−890.3kJ C2H4(g)+H2(g)⟶C2H6(g) ΔH∘=−136.3kJ 2H2(g)+O2(g)⟶2H2O(l) ΔH∘=−571.6kJ 2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(l ΔH∘=−3120.8kJ
9. Use the following experimentally derived combustion data to calculate the standard molar enthalpy of formation...
9. Use the following experimentally derived combustion data to calculate the standard molar enthalpy of formation (ΔH°f ) of liquid methanol (CH3OH) from its elements. 2 CH3OH(l) + 3 O2(g) → 2 CO2(g) + 4 H2O(l)     ΔH°rxn = −1452.8 kJ C(graphite) + O2(g) → CO2(g)                               ΔH°rxn = −393.5 kJ 2 H2(g) + O2(g) → 2 H2O(l)                                     ΔH°rxn = −571.6 kJ (1) −238.7 kJ/mol    (2) 487.7 kJ/mol       (3) −548.3 kJ/mol    (4) 20.1 kJ/mol         (5) 47.1 kJ/mol
We can use Hess's law to calculate enthalpy changes that cannot be measured. One such reaction...
We can use Hess's law to calculate enthalpy changes that cannot be measured. One such reaction is the conversion of methane to ethylene: 2CH4(g)⟶C2H4(g)+2H2(g) Part A Calculate the ΔH∘ for this reaction using the following thermochemical data: CH4(g)+2O2(g)⟶CO2(g)+2H2O(l) ΔH∘=−890.3kJ C2H4(g)+H2(g)⟶C2H6(g) ΔH∘=−136.3kJ 2H2(g)+O2(g)⟶2H2O(l) ΔH∘=−571.6kJ 2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(l) ΔH∘=−3120.8kJ Express your answer to four significant figures and include the appropriate units.
Given the following data: H2(g) + 1/2O2(g) → H2O(l) ΔH° = -286.0 kJ C(s) + O2(g)...
Given the following data: H2(g) + 1/2O2(g) → H2O(l) ΔH° = -286.0 kJ C(s) + O2(g) → CO2(g) ΔH° = -394.0 kJ 2CO2(g) + H2O(l) → C2H2(g) + 5/2O2(g) ΔH° = 1300.0 kJ Calculate ΔH° for the reaction: 2C(s) + H2(g) → C2H2(g)
Given the following reactions and their associated enthalpy changes    CO2 (g) →      C (s) +...
Given the following reactions and their associated enthalpy changes    CO2 (g) →      C (s) + O2 (g)                          ΔH = 393.5 kJ C3H8 (g) + 5 O2 (g) →     3 CO2 (g) + 4 H2O (g)   ΔH = -2044 kJ     H2 (g) + 1/2 O2 (g) →        H2O (g)                     ΔH = -241.8 kJ calculate the enthalpy change for the following reaction: 4 H2 (g) + 3 C (s)→ C3H8 (g)
Hess's law states that "the heat released or absorbed in a chemical process is the same...
Hess's law states that "the heat released or absorbed in a chemical process is the same whether the process takes place in one or in several steps." It is important to recall the following rules: When two reactions are added, their enthalpy values are added. When a reaction is reversed, the sign of its enthalpy value changes. When the coefficients of a reaction are multiplied by a factor, the enthalpy value is multiplied by that same factor. Part A Calculate...
Hess's Law Given the following data: 2C(s) + 2H2(g) + O2(g) → CH3OCHO(l) ΔH°=-366.0 kJ CH3OH(l)...
Hess's Law Given the following data: 2C(s) + 2H2(g) + O2(g) → CH3OCHO(l) ΔH°=-366.0 kJ CH3OH(l) + O2(g) → HCOOH(l) + H2O(l) ΔH°=-473.0 kJ C(s) + 2H2(g) + 1/2O2(g) → CH3OH(l) ΔH°=-238.0 kJ H2(g) + 1/2O2(g) → H2O(l) ΔH°=-286.0 kJ calculate ΔH° for the reaction: HCOOH(l) + CH3OH(l) → CH3OCHO(l) + H2O(l)
Given tha delta hydrogen = -393.5 kJ for the rxn.: C(s) +O2(g) -> CO2(g), and given...
Given tha delta hydrogen = -393.5 kJ for the rxn.: C(s) +O2(g) -> CO2(g), and given that delta Hydrogen = -285.8 kj for the rxn.: H2(g)+ 1/2O2(g) -> H2O(l), and given that delta hydrogen = -84.7 kJ for the rxn .: 3H2(g) +2C +2C(graphite) -> C2H6(g), calculate the dleta hydrogen for the rxn C2H6(g) + 3 1/2O2(g) -> 2CO2(g) + 3HO(l) Delta hydrogen = kJ
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT