A cell has a solute potential of -3.3 MPa and a pressure potential of 0.5 MPa, and it is placed in a sugar solution of water potential -1.0 MPa. Assume that the cell changes volume by 10%. Determine (a) the direction that water flows, and for the cell at equilibrium, (b) the solute potential, (c) pressure potential, and (d) overall water potential.
Water flows from higher water potential to lower water potential.
a. Here,solute potential of cell= -3.3 MPa
Pressure potential of cell = 0.5 MPa
WATER POTENTIAL OF CELL = Solute potential + Pressure potential
= -3.3 MPa + 0.5 MPa
= -2.8 MPa
The water potential of the sugar solution is -1.0 MPa.
Comparing,the sugar solution is having higher water potential(-1.0 MPa) than the cell (-2.8 MPa).So water flows from sugar solution to the cell.
By assuming that the volume of cell changed by 10%, the content in the cell decreased to 90% of the initial value.Therefore ;
b. the solute potential of cell at equilibrium = -3.3 * 90%
= -2.97 MPa
c.the pressure potential of cell at equilibrium = 1.97 MPa
d.water potential of cell at equilibrium = -1.0 MPa
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