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A cell has a solute potential of -3.3 MPa and a pressure potential of 0.5 MPa,...

A cell has a solute potential of -3.3 MPa and a pressure potential of 0.5 MPa, and it is placed in a sugar solution of water potential -1.0 MPa. Assume that the cell changes volume by 10%. Determine (a) the direction that water flows, and for the cell at equilibrium, (b) the solute potential, (c) pressure potential, and (d) overall water potential.

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Answer #1

Water flows from higher water potential to lower water potential.

a. Here,solute potential of cell= -3.3 MPa

Pressure potential of cell = 0.5 MPa

WATER POTENTIAL OF CELL = Solute potential + Pressure potential

= -3.3 MPa + 0.5 MPa

= -2.8 MPa

The water potential of the sugar solution is -1.0 MPa.

Comparing,the sugar solution is having higher water potential(-1.0 MPa) than the cell (-2.8 MPa).So water flows from sugar solution to the cell.

By assuming that the volume of cell changed by 10%, the content in the cell decreased to 90% of the initial value.Therefore ;

b. the solute potential of cell at equilibrium = -3.3 * 90%

= -2.97 MPa

c.the pressure potential of cell at equilibrium = 1.97 MPa

d.water potential of cell at equilibrium = -1.0 MPa

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