Question

A cell has a solute potential of -3.3 MPa and a pressure potential of 0.5 MPa,...

A cell has a solute potential of -3.3 MPa and a pressure potential of 0.5 MPa, and it is placed in a sugar solution of water potential -1.0 MPa. Assume that the cell changes volume by 10%. Determine (a) the direction that water flows, and for the cell at equilibrium, (b) the solute potential, (c) pressure potential, and (d) overall water potential.

Homework Answers

Answer #1

Water flows from higher water potential to lower water potential.

a. Here,solute potential of cell= -3.3 MPa

Pressure potential of cell = 0.5 MPa

WATER POTENTIAL OF CELL = Solute potential + Pressure potential

= -3.3 MPa + 0.5 MPa

= -2.8 MPa

The water potential of the sugar solution is -1.0 MPa.

Comparing,the sugar solution is having higher water potential(-1.0 MPa) than the cell (-2.8 MPa).So water flows from sugar solution to the cell.

By assuming that the volume of cell changed by 10%, the content in the cell decreased to 90% of the initial value.Therefore ;

b. the solute potential of cell at equilibrium = -3.3 * 90%

= -2.97 MPa

c.the pressure potential of cell at equilibrium = 1.97 MPa

d.water potential of cell at equilibrium = -1.0 MPa

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
If a plant cell with a solute potential of -0.2 MPa is placed in a beaker...
If a plant cell with a solute potential of -0.2 MPa is placed in a beaker of pure water, at equilibrium it will have a pressure potential of +0.2 MPa because the cell wall prevents cell expansion. If that cell is then placed in a solution with a solute potential of -0.3 MPa that is open to the atmosphere (draw a picture if it helps you), a.) Water will flow out of the cell b.) Water will flow into the...
Two cells A and B are contiguous. Cell A has osmotic pressure 10 atm, turgor pressure...
Two cells A and B are contiguous. Cell A has osmotic pressure 10 atm, turgor pressure 7 atm and diffusion pressure deficit 3 atm. Cell B has osmotic pressure 8 atm, turgor pressure 3 atm and diffusion pressure deficit 5 atm. The result will be (a) no movement of water (b) equilibrium between the two (c) movement of water from cell A to B (d) movement of water from cell B to A.
Water at 0.5 quality is heated from 0.2 MPa to 200°C at a fixed volume. What...
Water at 0.5 quality is heated from 0.2 MPa to 200°C at a fixed volume. What is the final pressure? Choose the closest value a. 285 kPa b. 172 kPa c. 505 kPa d. 1156 kPa e. 795 kPa
As solute is dissolved in a solvent, the vapor pressure of the solution changes according to...
As solute is dissolved in a solvent, the vapor pressure of the solution changes according to Raoult's law Psoln=Psolv×Xsolv where Psoln is the vapor pressure of the solution, Psolv is the vapor pressure of the pure solvent, and Xsolv is the mole fraction of the solvent. If the solute dissociates into ions, the term Xsolv must be modified to take into consideration the total number of moles of particles in the solution, both ions and molecules. When a solution contains...
3. Determine the pH of a buffer that contains 0.5 mole HOCl and 0.5 mole NaOCl...
3. Determine the pH of a buffer that contains 0.5 mole HOCl and 0.5 mole NaOCl in a total volume of 1.0 L. The Ka of HOCl is 3.5 x 10^-8. 4. Write a net ionic Equation for what happens when NaOH is added into the solution in number 3. 5. Determine the pH when 0.1 mole NaOH is added to the solution in number 3. Assume the total volume does not change. 6. Determine the pH when 0.1 mole...
Steam has 1.0 MPa, 80% dryness-2 fraction,This steam is placed in a piston cylinder at constant...
Steam has 1.0 MPa, 80% dryness-2 fraction,This steam is placed in a piston cylinder at constant pressure and heated until its final volume became 0.2 m3. So, the amount of .heat transfer 687.25 kJ O -687.25kJ O 788.83 kJ O -788.83 kJ You need a solution within ten minutes necessary
2. A geothermal power plant is supplied with water at 260°C and a pressure of 10...
2. A geothermal power plant is supplied with water at 260°C and a pressure of 10 MPa. The fluid flows to a flash unit, exiting as liquid and vapor streams at 0.5 bar. Vapor from the flash unit is fed to a turbine. The turbine exit pressure is 0.02 bar. The overall turbine efficiency is 0.83. Calculate the thermal efficiency, the heat rate, and steam and water mass flow rates required for an output of 5 MW. Can someone help,...
A student measures the potential of a cell made up with 1.0 M CuSO4 in one...
A student measures the potential of a cell made up with 1.0 M CuSO4 in one solution and 1.0 M AgNO3 in the other. There is a Cu electrode in the CuSO4 and a Ag electrode in the AgNO3. A salt bridge connects the 2 half cells. The student finds that the potential, or voltage of the cell, E°cell is 0.45 V and that the Cu electrode is negative. a. At which electrode is the oxidation occurring? ___________ b. Write...
A 500.0 mL solution of NaNO3 in water has a vapor pressure of 21.445 mm Hg...
A 500.0 mL solution of NaNO3 in water has a vapor pressure of 21.445 mm Hg at 25°C. How many grams of NaNO3 (molar mass = 84.994 g/mol) were added to the water if the vapor pressure of pure water at 25°C is 23.76 mm Hg. Assume the volume of the water (d = 1.000 g/mL) is the same as the volume of the solution.
1. in order for a solute to be dissolved in water it has to a) be...
1. in order for a solute to be dissolved in water it has to a) be an ionic compound b) be a polar compound c) be a nonpolar compound d) A and B 2. Hydrophobic exclusion drives the spontaneous formation of which of the following a) cell membranes b) proteins c) oil layer in salad dressing d) all of the above