Question

For the purposes of this problem we will ignore the fact that viral genomes can also be segmented or nonsegmented.You will need to do some outside research and examine the functional differences between two types of enzymes: exonucleases and endonucleases.

Suppose four viral genomes were examined in the laboratory. The following information was obtained for each viral genome:

Genome of virus 1: A = 28%, C= 22%, G = 24%, T = 0%, U = 26%, resistant to exonucleases but sensitive to endonucleases.

Genome of virus 2: A = 34%, C = 37%, G = 14%, T = 0%, U = 15%, sensitive to both exonucleases and endonucleases.

Genome of virus 3: A = 20%, C = 30%, G = 32%, T = 18%, U = 0%, sensitive to both exonucleases and endonucleases.

Genome of virus 4: A = 18%, C = 33%, G = 24%, T = 25%, U = 0%; resistant to exonucleases but sensitive to endonucleases.

Note: the single letter codes (A, U, etc.) represent the DNA/RNA nucleotides.

What is the structure of the nucleic acid in each viral genome? Be sure to include in each answer double-stranded vs. single-stranded, DNA vs. RNA, and circular vs. linear

Answer 1

Answer.

DNA consists of nitrogen bases, adenine, guanine, thymine and cytosine.

RNA consists of adenine, guanine, uracil and cytosine.

Double stranded= number of purines= number of pyrimidine

A=T and G=C

Genome of virus 1: A = 28%, C= 22%, G = 24%, T = 0%, U = 26%, resistant to exonucleases but sensitive to endonucleases.------RNA, single stranded and circular.

Genome of virus 2: A = 34%, C = 37%, G = 14%, T = 0%, U = 15%, sensitive to both exonucleases and endonucleases.---RNA, single stranded and linear.

Genome of virus 3: A = 20%, C = 30%, G = 32%, T = 18%, U = 0%, sensitive to both exonucleases and endonucleases.----DNA, single stranded and linear.

Genome of virus 4: A = 18%, C = 33%, G = 24%, T = 25%, U = 0%; resistant to exonucleases but sensitive to endonucleases.---DNA, single stranded and circular