A man and a woman who are both carriers of cystic fibrosis have had three children without cystic fibrosis. If the couple has a fourth child, what is the probability that the child will have the disorder?
Question 4 options:
a)
1/4
b)
1/5
c)
1/8
d)
2/4
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Hi Answer:
Q. A man and a woman who are both carriers of cystic fibrosis have had three children without cystic fibrosis. If the couple has a fourth child, what is the probability that the child will have the disorder?
Answer: Option A (1/4 i.e 25%)
Explanation: Both parents are the carrier of the disease means they are heterozygous for the disease. There are ¼ chances that their child will inherit the disease. In the present case, both parents are the carrier of the disease they don’t have actually the disease. The full chances (100%) chances for disease in a child is only possible when both are homozygous for disease and when one of the parents is homozygous for disease and another is heterozygous then chances are 50%.
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