Question

In the experiment you are working on, samples of the enzyme and samples of the substrate...

In the experiment you are working on, samples of the enzyme and samples of the substrate are often preonvunared separately before they are mixed to observe the reaction. What is the purpose of this preincubation?

Homework Answers

Answer #1

Whenever we set the enzymatic reaction we take out enzyme from either -20 degree or 4-degree temperature which is different from the temperature at which the enzyme shows its activity. In case of the substrate, we need to bring it to the temperature at which enzyme can efficiently act on it and catalyse the reaction. Preincubation brings both the enzyme as well as substrate at the optimum temperature of the enzyme where the enzyme starts its activity as soon as we add the substrate

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Experiment II: Effect of Substrate Concentration on the Rate of Enzyme Reaction What does this influence...
Experiment II: Effect of Substrate Concentration on the Rate of Enzyme Reaction What does this influence indicate about the enzyme function?
How would you describe the relative proportions of substrate and enzyme in a biological reaction?
How would you describe the relative proportions of substrate and enzyme in a biological reaction?
An enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than...
An enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than the Km for that substrate. After 9 minutes, 1% of the substrate had been converted to product, and the amount of product formed in the reaction mixture was 12 mmol. If, in a separate experiment, one-third as much enzyme and twice as much substrate had been combined, how long would it take for the same amount (12 mmol) of product to be formed?
20. You run a reaction with 1 µg of enzyme QB26, buffer and 25 millimolar (mM)...
20. You run a reaction with 1 µg of enzyme QB26, buffer and 25 millimolar (mM) substrate and obtain an initial reaction velocity (vo) of 100micromolar (µM) product per second. You repeat the reaction the same as before but with 50 mM substrate and observe vo = 101µM/sec, repeat at 100mM substrate, get vo =102µM/sec. a. The substrate concentrations in these reactions are very close the Km b. The velocities in these reactions are very close to Vmax c. The...
An enzyme-catalyzed reaction was carried out with the substrate concentration initially 3500 times greater than the...
An enzyme-catalyzed reaction was carried out with the substrate concentration initially 3500 times greater than the Km for that substrate. After 9 minutes, 1% of the substrate had been converted to product, and the amount of product formed in the reaction mixture was 12 micro-moles. If, in a separate experiment, the same amount of substrate but six times as much enzyme had been combined in the same volume, how long would it take for the same amount (12 micro-moles) of...
An enzyme-catalyzed reaction was carried out with the substrate concentration initially two hundred times greater than...
An enzyme-catalyzed reaction was carried out with the substrate concentration initially two hundred times greater than the Km for that substrate. After 5 minutes, 1% of the substrate had been converted to product, and the amount of product formed in the reaction mixture was 30 micro mol. If, in a seperate experiment, TWO TIMES MORE enzyme and twice as much substrate had been combined, how long would it take for the same amount (30 micro mol) of product to be...
An enzyme-catalyzed reaction was carried out with the substrate concentration initially three hundred times greater than...
An enzyme-catalyzed reaction was carried out with the substrate concentration initially three hundred times greater than the Km for that substrate. After five minutes, 1% of the substrate had been converted to product, and the amount of product formed in the reaction mixture was 15 micro moles. If, in a seperate experiment, four times less enzyme and twice as much substrate had been combined, how long would it take for the same amount (15 micro moles) of product to be...
1.Imagine that you are observing an enzyme-catalyzed reaction in lab. Every time you add more enzyme,...
1.Imagine that you are observing an enzyme-catalyzed reaction in lab. Every time you add more enzyme, the reaction rate increases proportionally until the reaction rate suddenly levels off. No other chemicals were added, and no modifications were made in the experimental setting. Why do you think the reaction rate stopped increasing? Select one: a. The molecules of substrate were all bound to enzyme. b. The molecules of substrate noncompetitively inhibited the enzyme. c. The molecules of product competitively inhibited the...
a) The Km of an enzyme of an enzyme-catalyzed reaction is 7.5 µM. What substrate concentration...
a) The Km of an enzyme of an enzyme-catalyzed reaction is 7.5 µM. What substrate concentration will be required to obtain 65% of Vmax for this enzyme? (same enzyme was used in part a and b) b) Calculate the Ki for a competitive inhibitor whose concentration is 7 x10-6 M. The Km in the presence of inhibitor was found to be 1.2x10-5 M. 
An enzyme is discovered that converts substrate A to product B. The molecular weight of the...
An enzyme is discovered that converts substrate A to product B. The molecular weight of the enzyme is 10000 Daltons. The Km and Vmax values for the enzyme are shown below: Km (mM) 2 Vmax (mmole/min/mg) 20 What is the reaction initial velocity for this enzyme when the concentration of A is 4 mM? What is the turnover number of this enzyme?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT