Question

(1 point) Solve the initial value problem 10(t+1)dydt−8y=16t, for t>−1 with y(0)=2. y=

(1 point) Solve the initial value problem

10(t+1)dydt−8y=16t,


for t>−1 with y(0)=2.
y=

Homework Answers

Answer #1

if you have any doubt about solution ask me in comment section I will explain

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Solve the initial value problem 9(t+1) dy dt −6y=18t, 9(t+1)dydt−6y=18t, for t>−1 t>−1 with y(0)=14. y(0)=14....
Solve the initial value problem 9(t+1) dy dt −6y=18t, 9(t+1)dydt−6y=18t, for t>−1 t>−1 with y(0)=14. y(0)=14. Find the integrating factor, u(t)= u(t)= , and then find y(t)= y(t)=
solve the initial value problem y''+8y=cos(3t), y(0)=1, y'(0)=-1
solve the initial value problem y''+8y=cos(3t), y(0)=1, y'(0)=-1
Solve the given initial-value problem. y'' + 7y' − 8y = 16e2x,    y(0) = 1, y'(0) =...
Solve the given initial-value problem. y'' + 7y' − 8y = 16e2x,    y(0) = 1, y'(0) = 1
Solve the initial value problem 2(sin(t)dydt+cos(t)y)=cos(t)sin^3(t) for 0<t<π0<t<π and y(π/2)=13.y(π/2)=13. Put the problem in standard form....
Solve the initial value problem 2(sin(t)dydt+cos(t)y)=cos(t)sin^3(t) for 0<t<π0<t<π and y(π/2)=13.y(π/2)=13. Put the problem in standard form. Then find the integrating factor, ρ(t)= and finally find y(t)=
use the Laplace transform to solve the following initial value problem y”+8y’+25y=&(t-8) y(0)=0 y’(0)=0 use step...
use the Laplace transform to solve the following initial value problem y”+8y’+25y=&(t-8) y(0)=0 y’(0)=0 use step (t-c) for uc(t)
Solve the initial-value problem for linear differential equation y'' + 4y' + 8y = sinx; y(0)...
Solve the initial-value problem for linear differential equation y'' + 4y' + 8y = sinx; y(0) = 1, y'(0) = 0
Solve the initial value problem 3y'(t)y''(t)=16y(t) , y(0)=1, y'(0)=2
Solve the initial value problem 3y'(t)y''(t)=16y(t) , y(0)=1, y'(0)=2
Solve the initial value problem y"+2y'-8y=14e^(3t) y(0)=8, y'(0)=6
Solve the initial value problem y"+2y'-8y=14e^(3t) y(0)=8, y'(0)=6
For the initial value problem • Solve the initial value problem. y' = 1/2−t+2y withy(0)=1
For the initial value problem • Solve the initial value problem. y' = 1/2−t+2y withy(0)=1
solve the initial value problem y' y" - t = 0 y(1) = 2 y'(1) =1
solve the initial value problem y' y" - t = 0 y(1) = 2 y'(1) =1
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT