Question

Solve the initial value problem 9(t+1) dy dt −6y=18t, 9(t+1)dydt−6y=18t, for t>−1 t>−1 with y(0)=14. y(0)=14. Find the integrating factor, u(t)= u(t)= , and then find y(t)= y(t)=

Answer #1

Solve the initial value problem 8(t+1)dy/dt - 6y = 12t
for t > -1 with y(0) = 7
7 =

Solve the initial value problem 8(t+1)dy/dt−6y=12t, for t>−1
with y(0)=11.

Solve the Initial Value Problem:
a) dydx+2y=9, y(0)=0 y(x)=_______________
b) dydx+ycosx=5cosx,
y(0)=7d y(x)=______________
c) Find the general solution, y(t), which solves the problem
below, by the method of integrating factors.
8t dy/dt +y=t^3, t>0
Put the problem in standard form.
Then find the integrating factor, μ(t)= ,__________
and finally find y(t)= __________ . (use C as the unkown
constant.)
d) Solve the following initial value problem:
t dy/dt+6y=7t
with y(1)=2
Put the problem in standard form.
Then find the integrating...

Solve the Initial Value Problem:
dydx+2y=9,
y(0)=0
dydx+ycosx=5cosx,
y(0)=7d
Find the general solution, y(t)y(t), which solves the problem
below, by the method of integrating factors.
8tdydt+y=t3,t>08tdydt+y=t3,t>0
Put the problem in standard form.
Then find the integrating factor,
μ(t)=μ(t)= ,__________
and finally find y(t)=y(t)= __________ . (use C as the
unkown constant.)
Solve the following initial value problem:
tdydt+6y=7ttdydt+6y=7t
with y(1)=2.y(1)=2.
Put the problem in standard form.
Then find the integrating factor, ρ(t)=ρ(t)= _______ ,
and finally find y(t)=y(t)= _________ .

Solve the initial value problem
t^(13) (dy/dt) +2t^(12) y =t^25 with t>0 and y(1)=0
(y'-e^-t+4)/y=-4, y(0)=-1

Solve the initial value problem
2(sin(t)dydt+cos(t)y)=cos(t)sin^3(t)
for 0<t<π0<t<π and y(π/2)=13.y(π/2)=13.
Put the problem in standard form.
Then find the integrating factor, ρ(t)=
and finally find y(t)=

(1 point) Solve the initial value problem
10(t+1)dydt−8y=16t,
for t>−1 with y(0)=2.
y=

1. Solve the following initial value problem using Laplace
transforms.
d^2y/dt^2+ y = g(t) with y(0)=0 and dy/dt(0) = 1 where g(t) = t/2
for 0<t<6 and g(t) = 3 for t>6

solve the given initial value problem
dx/dt=7x+y x(0)=1
dt/dt=-6x+2y y(0)=0
the solution is x(t)= and y(t)=

Consider the differential equation y′′+ 9y′= 0.(
a) Let u=y′=dy/dt. Rewrite the differential equation as a
first-order differential equation in terms of the variables u.
Solve the first-order differential equation for u (using either
separation of variables or an integrating factor) and integrate u
to find y.
(b) Write out the auxiliary equation for the differential
equation and use the methods of Section 4.2/4.3 to find the general
solution.
(c) Find the solution to the initial value problem y′′+ 9y′=...

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