Question
= ((0.85)(55)(500x425)+((550-0.85x55)(3600))x10^-3
=
((0.85)(55)(500x425)+((550-0.85x55)(3600))x10^-3
Homework Answers
Answer #1
Not the answer you're looking for?
Similar Questions
For a 3p electron in an external magnetic field of 1.90 x10-3 T, find the following....
For a 3p electron in an external magnetic field of 1.90
x10-3 T, find the following.
(a)the current (in A) associated with the orbital angular
momentum
(b)the maximum torque (in N · m)
A solution is made from 25 mL of 2.00x10^-2 M AgNO3 and 10mL of 6.00 x10^-2...
A solution is made from 25 mL of 2.00x10^-2 M AgNO3
and 10mL of 6.00 x10^-2 M Na3AsO4. The Ksp of Ag3AsO4 is 1.00
x10^-22. Does a precipitate form? Show all calculations.
Ag3AsO4 (s) <----> 3 Ag+(aq) + AsO4^3- (aq)
The molar solubility of AgCl in 6.5 x10^-3 M AgNO3 is 2.5x10^-8 M. In deriving Ksp...
The molar solubility of AgCl in 6.5 x10^-3 M AgNO3 is 2.5x10^-8
M. In deriving Ksp from these data, which of the following
assumptions is (are) reasonable
A. Ksp is the same as solubility
B. Ksp of AgCl is the same in 2.5x10^-8 M AgNO3 as in pure
water
C. Solubility of AgCl is independent of the concentration of
AgNO3
D. [Ag+] does not change significantly upon addition of AgCl to
6.5x10^-3 M AgNO3
E. [Ag+] after the addition of...
What is the remainder when the poynomial x53-1240-3x27-5x21+x10-3 is divided by x+1? The possible answers were...
What is the remainder when the poynomial
x53-1240-3x27-5x21+x10-3
is divided by x+1? The possible answers were -21, -7, -3, 4, and
21. -7 was the correct answer and I'm unsure how they arrived at a
single answer without x appearing. If you could show all the steps
that would be excellent. Thanks
Copper has 8.5 x10^28 electrons per m^3 . A 71 cm length of copper wire of...
Copper has 8.5 x10^28 electrons per m^3 . A 71 cm length of
copper wire of diameter 2.05 mm carries 4.85A of current. ( For
copper: ρ = 1.72 x 10^-8 ohm-m) a. How much time does it take an
electron to travel the length of the wire ? b. Find the electric
field inside the wire. c. What is the resistance of this wire?
Lbs plastic waste 0.27 1.41 2.19 2.83 2.19 1.81 0.85 3.05 # in household 2 3...
Lbs plastic waste
0.27
1.41
2.19
2.83
2.19
1.81
0.85
3.05
# in household
2
3
3
6
4
2
1
5
What is the linear correlation between list of plastic waster
per week and household size?
What is the proportion of variance explained (coefficient of
determination)?
Predict the number of people in a household with 2.5lbs of
waste
A three-phase Wye-connected synchronous generator is rated 3600 rpm, 200kVA, 480V, 60 Hz. The generator’s armature...
A three-phase Wye-connected synchronous generator is rated 3600
rpm, 200kVA, 480V, 60 Hz. The generator’s armature winding
resistance is RA = 0.03Ω and the synchronous reactance
XS is 0.25Ω. The rotational losses are 6kW, the core
losses are 4kW, and the stray losses are 1% of the output real
power. The generator is delivering 200kVA power at 0.85 pf lagging
at rated voltage. Taking the phase voltage at the output as a
reference, answer the following questions.
How many poles...
3. Light of wavelength 550 nm is incident on a diffraction grating that is 1 cm...
3. Light of wavelength 550 nm is incident on a diffraction
grating that is 1 cm wide and has 1000 slits. What is the
dispersion of the m=2 line?
I believe the answer is 2.0 x 10^5 rad/m, however, haven't been
able to get that as an answer.
I believe i'm supposed to start with the Dispersion equation D=
(Change in theta / Change in Lambda) = m/(dcos(theta)).
Any direction is helpful, thank you!
A tank having a volume of 0.85 m^3 initially contains water as a two-phase liquid vapor...
A tank having a volume of 0.85 m^3 initially contains water as a
two-phase liquid vapor mixture at 260 C and a quality of 0.7.
Saturated water vapor at 260 C is slowly withdrawn through a
pressure-regulating valve at the top of the tank as energy is
transferred by heat to maintain the pressure constant in the tank.
This continues until the tank is filled with saturated vapor at 260
C. Determine the amount of heat transfer in kJ. Neglect...
An engine running at a temperature of 25°C is fueled by a constant 0.05 l/s gas...
An engine running at a temperature of 25°C is fueled by a
constant 0.05 l/s gas flow via a pipe with a diameter of 3.0 cm. At
25°C the gas has a viscosity of 0.85 mPa · s. If the engine runs in
a hotter environment, its temperature increases to 55 °C. Determine
Reynolds number and the type of gas flow through the pipe at 55 °C,
knowing that the gas density is 1,100 kg/m3 at all
temperatures and the...
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 2 minutes ago
asked 36 minutes ago
asked 45 minutes ago
asked 48 minutes ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 2 hours ago
asked 2 hours ago
asked 2 hours ago
asked 2 hours ago