For a 3p electron in an external magnetic field of 1.90 x10-3 T, find the following.
(a)the current (in A) associated with the orbital angular momentum
(b)the maximum torque (in N · m)
part A : angular momentm L = mvr = nh/2pi
L = 3* 6.624*10^-34/(2pi)
L = 3.16*10^-34 kgm/s
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time T = 2pi R /Vn
Vn = n^2 * (0.529 )*10^-9/Z
Vn = 3^2 * 0.529 *10^-9 /1
Vn = 4.761 *10^-9 m/s
now use Time = 2piR/Vn
R = 0.529 E-9
Current I = chrage/time
I = 1.6*10^-19/time
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b) TOrque T = u x B
B is given in the question
u =magnetic moment = i x A
A is area = pir ^2
find torque now
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