Question

The original problem is: y''+y^2=1 with initial values y(0)=2 and y'(0)=3. Instructions ask to use the...

The original problem is: y''+y^2=1 with initial values y(0)=2 and y'(0)=3. Instructions ask to use the appropiate substitution method. I was able to solve the problem by using a taylor expansion centered on 0. But it seems like the problem wants it to be solved by using the method of substitution when f(y'',y',y) and there is no independent variable.

Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Solutionm;-

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Using Taylor series expansion method; find a series solution of the initial value problem (x2+1)d2y/dx2+xdy/dx+2xy=0 y(0)=2...
Using Taylor series expansion method; find a series solution of the initial value problem (x2+1)d2y/dx2+xdy/dx+2xy=0 y(0)=2 y'(0)=1
Solve the initial value problem: 4y′′+3y=0, y(π/2)=2 , y'(π/2)=−1. Give your answer as y=... Use x...
Solve the initial value problem: 4y′′+3y=0, y(π/2)=2 , y'(π/2)=−1. Give your answer as y=... Use x as the independent variable.
Solve the initial value problem: y′′−2y′+11y=0y″−2y′+11y=0, y(0)=3y(0)=3, y′(0)=−3.y′(0)=−3.Give your answer as y=... y=... . Use xx...
Solve the initial value problem: y′′−2y′+11y=0y″−2y′+11y=0, y(0)=3y(0)=3, y′(0)=−3.y′(0)=−3.Give your answer as y=... y=... . Use xx as the independent variable.
Solve the initial value problem: 9y″+18y′+19y=0, y(π/2)=−2, y′(π/2)=−2. Give your answer as y=... . Use x...
Solve the initial value problem: 9y″+18y′+19y=0, y(π/2)=−2, y′(π/2)=−2. Give your answer as y=... . Use x as the independent variable.
Solve the initial value problem: 9y′′−18y′+15y=09y″−18y′+15y=0, y(π/3)=2y(π/3)=2, y′(π/3)=1.y′(π/3)=1.Give your answer as y=... y=... . Use xx...
Solve the initial value problem: 9y′′−18y′+15y=09y″−18y′+15y=0, y(π/3)=2y(π/3)=2, y′(π/3)=1.y′(π/3)=1.Give your answer as y=... y=... . Use xx as the independent variable.
Solve the initial-value problem. y"-6y'+9y=0; y(0)=2, y'(0)=3 Given that y1=x2 is a solution to y"+(1/x) y'-(4/x2)...
Solve the initial-value problem. y"-6y'+9y=0; y(0)=2, y'(0)=3 Given that y1=x2 is a solution to y"+(1/x) y'-(4/x2) y=0, find a second, linearly independent solution y2. Find the Laplace transform. L{t2 * tet} Thanks for solving!
2. Solve the initial-value problem: y′′′ + 4y′ = t, y(0) = y′(0) = 0, y′′(0)...
2. Solve the initial-value problem: y′′′ + 4y′ = t, y(0) = y′(0) = 0, y′′(0) = 1.
Solve the initial value problem below using the method of Laplace transforms. y''-y'-30y=0, y(0) = 4...
Solve the initial value problem below using the method of Laplace transforms. y''-y'-30y=0, y(0) = 4 , y'(0) = 46 y(t) = ?
Solve the initial value problem: y''−2y'+y=e^t/(1+t^2), y(0) = 1, y'(0) = 0.
Solve the initial value problem: y''−2y'+y=e^t/(1+t^2), y(0) = 1, y'(0) = 0.
Solve the Initial Value Problem: ?x′ = 2y−x y′ = 5x−y Initial Conditions: x(0)=2 y(0)=1
Solve the Initial Value Problem: ?x′ = 2y−x y′ = 5x−y Initial Conditions: x(0)=2 y(0)=1
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT