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Solve the initial value problem: 9y′′−18y′+15y=09y″−18y′+15y=0, y(π/3)=2y(π/3)=2, y′(π/3)=1.y′(π/3)=1.Give your answer as y=... y=... . Use xx...

Solve the initial value problem: 9y′′−18y′+15y=09y″−18y′+15y=0, y(π/3)=2y(π/3)=2, y′(π/3)=1.y′(π/3)=1.Give your answer as y=... y=... . Use xx as the independent variable.

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