Question

The solution of ẍ+ x = 0; x(0) = 0 ẋ(0) = 4 is:

The solution of ẍ+ x = 0; x(0) = 0 ẋ(0) = 4 is:

Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Find the general solution of the given system. X' = 12 -9 4 0 X
Find the general solution of the given system. X' = 12 -9 4 0 X
dx/dt=(1/4)x^3 -x, c(0)=1 compute the solution to this initial value problem. An algebraically implicit solution for...
dx/dt=(1/4)x^3 -x, c(0)=1 compute the solution to this initial value problem. An algebraically implicit solution for x(t) is acceptanle x(0)=1
Solve the Initial value porblem dx/dt=[-4 -4, 4 -4]x x(0)=[9 6] give your solution in real...
Solve the Initial value porblem dx/dt=[-4 -4, 4 -4]x x(0)=[9 6] give your solution in real form x1= x2=
In Exercises 1-20, find a general solution of the Cauchy-Euler equation. (Assume x > 0). 4(x^(2))y''+17y=0
In Exercises 1-20, find a general solution of the Cauchy-Euler equation. (Assume x > 0). 4(x^(2))y''+17y=0
The solution to the Initial value problem x′′+2x′+2x=2cos(7t),x(0)=0,x′(0)=0 is the sum of the steady periodic solution...
The solution to the Initial value problem x′′+2x′+2x=2cos(7t),x(0)=0,x′(0)=0 is the sum of the steady periodic solution xsp and the transient solution xtr. Find both xsp and xtr. xsp= xtr=
Find a particular solution consider x(0) = 1, x′(0) = −1, and x′′(0) = 0. x′′′...
Find a particular solution consider x(0) = 1, x′(0) = −1, and x′′(0) = 0. x′′′ -x′′ -x′ +x = 0
find the solution of the initial value-boundry vaule problem 8uxx=ut 0<x<8 t>=0 u(0,t)=0 u(8,t) = 4...
find the solution of the initial value-boundry vaule problem 8uxx=ut 0<x<8 t>=0 u(0,t)=0 u(8,t) = 4 u(x,0) = x
1) x(t+2) = x(t+1) + x(t) , t >=0 determine a closed solution (i.e. a solution...
1) x(t+2) = x(t+1) + x(t) , t >=0 determine a closed solution (i.e. a solution dependent only on time t ) for above eqn. Verify your answer by evaluating your solution at t = 0 , 1, 2, 3, 4, 5. We are given x(0) = 1 and x(1) = 1
Find the solution of the initial-value problem. y'' + y = 4 + 3 sin(x), y(0)...
Find the solution of the initial-value problem. y'' + y = 4 + 3 sin(x), y(0) = 7, y'(0) = 1
The DE (4+t^2)x''-2x=0 has a solution of the form x=a+bt+ct^2. Find a, b, c.
The DE (4+t^2)x''-2x=0 has a solution of the form x=a+bt+ct^2. Find a, b, c.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT