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The DE (4+t^2)x''-2x=0 has a solution of the form x=a+bt+ct^2. Find a, b, c.

The DE (4+t^2)x''-2x=0 has a solution of the form x=a+bt+ct^2. Find a, b, c.

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Answer #1

Given D.E. has solution of the form x=a+bt+ct^2 then there is not unique a,b,c .Here one variable is depends on other.That is one variable is free therefore a=4p,b=0,c=p where p is any real number.thank you.answer is below .

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