Question

solve 3y''' +5y'' + 10y' -4y=0

through and auxiliary equation

Answer #1

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Solve the differential equation by variation of parameters.
5y'' − 10y' + 10y = ex sec(x)
y(x) = ______.

Solve the equation
y''−5y' + 4y = f(t)
with
f(t) = 1 (0 ≤ t ≤ 5), f(t) = 0 (t > 5). and y(0) = 0 ,y'(0) =
1

Use Laplace Transforms to solve the following IVPs .
4y′′+4y′+5y=−t ; y(0)=0 , y′(0)=0

5. Solve the Bernouilli equation dx/dx = 5y^2 + 4y/x .

solve
y"-4y+5y=20 sehnt, y(0)=0, y'(0)=0

Solve the differential equation dy/dx = 10x + 5y/ 5x + 10y
Write your solution without logarithms, and use a single,
consolidated c as a constant.

Given the differential equation to the right y''-3y'+2y=0
a) State the auxiliary equation.
b) State the general solution.
c) Find the solution given the following initial conditions
y(0)=4 and y'(0)=5

Use the definition of the Laplace transform to solve the
IVP:
4y''− 4y' + 5y = δ(t), y(0) = −1, y'(0) = 0.

solve the IVP
y'' - 4y' - 5y = 6e-x, y(0)= 1, y'(0) =
-2

y'' + 4y' + 5y = δ(t − 2π),
y(0) = 0, y'(0) = 0
Solve the given IVP using the Laplace Transform. any help
greatly appreciated :)

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