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y''-25y=0 y(1)=e^(5x) use substitution y=ue^(5x) to find the second solution (x^2)y''-7xy'+16y=0 y(1)=x^4 use substitution y=ux^4 to...

y''-25y=0 y(1)=e^(5x) use substitution y=ue^(5x) to find the second solution

(x^2)y''-7xy'+16y=0 y(1)=x^4 use substitution y=ux^4 to find the second solution
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