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Given the second order initial value problem y′′+25y=5δ(t−1),  y(0)=2,  y′(0)=−10y″+25y=5δ(t−1),  y(0)=2,  y′(0)=−10Let Y(s)Y(s) denote the Laplace transform of yy. Then...

Given the second order initial value problem y′′+25y=5δ(t−1),  y(0)=2,  y′(0)=−10y″+25y=5δ(t−1),  y(0)=2,  y′(0)=−10Let Y(s)Y(s) denote the Laplace transform of yy. Then

Y(s)=Y(s)=  .

Taking the inverse Laplace transform we obtain y(t)=

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