Question

Find the solution of the initial value problem 16y′′−y=0, y(−4)=1 and y′(−4)=−1

Find the solution of the initial value problem 16y′′−y=0, y(−4)=1 and y′(−4)=−1

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Find the solution of the initial value problem y′′+16y′+63y=0, y(0)=7 and y′(0)=−59. y(t)=
Find the solution of the initial value problem y′′+16y′+63y=0, y(0)=7 and y′(0)=−59. y(t)=
Find the Laplace transform Y(s)=L{y} of the solution of the given initial value problem. A. y′′+16y...
Find the Laplace transform Y(s)=L{y} of the solution of the given initial value problem. A. y′′+16y = {1, 0 ≤ t < π = {0, π ≤ t < ∞, y(0)=3, y′(0)=5 B. y′′ + 4y = { t, 0 ≤ t < 1 = {1, 1 ≤ t < ∞, y(0)=3, y′(0)=3
Solve the initial value problem 3y'(t)y''(t)=16y(t) , y(0)=1, y'(0)=2
Solve the initial value problem 3y'(t)y''(t)=16y(t) , y(0)=1, y'(0)=2
Solve the initial value problem: y”+16y’+64y=7e^(-t) y(0)=0, y’(0)=0
Solve the initial value problem: y”+16y’+64y=7e^(-t) y(0)=0, y’(0)=0
Find the solution of the initial-value problem. y'' + y = 4 + 3 sin(x), y(0)...
Find the solution of the initial-value problem. y'' + y = 4 + 3 sin(x), y(0) = 7, y'(0) = 1
2. Find the solution of the initial value problem y''−y=0, y(0) = 5/4, y'(0) =−3/4.
2. Find the solution of the initial value problem y''−y=0, y(0) = 5/4, y'(0) =−3/4.
Find the solution of the given initial value problem: y(4)+2y′′+y=5t+2; y(0)=y′(0)=0, y′′(0)=y'''(0)=1
Find the solution of the given initial value problem: y(4)+2y′′+y=5t+2; y(0)=y′(0)=0, y′′(0)=y'''(0)=1
Find the solution to the initial-value problem: y''+4y=2sin(2x), y(0)=1, y'(0)=0
Find the solution to the initial-value problem: y''+4y=2sin(2x), y(0)=1, y'(0)=0
Find the solution of the initial value problem y′′+4y=t^2+4^(et), y(0)=0, y′(0)=3.
Find the solution of the initial value problem y′′+4y=t^2+4^(et), y(0)=0, y′(0)=3.
differential equations find the solution to the initial value problem y’’ + y(x^2) = 0 y(0)...
differential equations find the solution to the initial value problem y’’ + y(x^2) = 0 y(0) = 0 y’(0) = 0